-3T=p^2-Q

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Solution for -3T=p^2-Q equation: 



-3=T^2-

We move all terms to the left:

-3-(T^2-)=0

We get rid of parentheses

-T^2-3+=0

We add all the numbers together, and all the variables

-1T^2=0

a = -1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-1)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$T=\frac{-b}{2a}=\frac{0}{-2}=0$

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